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# [Solution] Make Multiple CodeChef Solution

## Problem

Chef has two integers $A$ and $B$ $(A \leq B)$.

Chef can choose any non-negative integer $X$ and add them to both $A$ and $B$. Find whether it is possible to make $A$ a divisor of $B$.

### Input Format

• The first line of input will contain a single integer $T$, denoting the number of test cases.
• Each test case consists of two integers $A$ and $B$.

### Output Format

For each test case, output YES if it is possible to make $A$ a factor of $B$NO otherwise.

You can print each character of the string in uppercase or lowercase. For example, the strings YesYESyes, and yEs, are all considered identical.

### Explanation:

Test case $1$: We can choose $X = 0$ and add them to $3$ and $6$. Thus, $3$ is a factor of $6$.

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Test case $2$: We can choose $X = 1$ and add them to $4$ and $14$. Thus, $4+1 = 5$ is a factor of $14+1 = 15$.

Test case $3$: There is no possible value of $X$ to add such that $A$ becomes a factor of $B$.